What is the empirical formula for propene (c3h6)? c2h4 c4h8 c3h6 ch2

Answers

To determine the empirical formula or the simplest ratio of specific atoms to other atoms in a given compound, simply divide by the largest common divisible factor of the subscripts in this case it's 3.

C3H6 -> CH2.
CH2 all you do is divide by 3 

The empirical formula is the simplest formula attainable while maintaining the ratio so it will be CH2.

Explanation:

The empirical formula of a chemical compound is the simplistic positive integer ratio of atoms being in a compound. A simple example of this thought is that the empirical formula of sulfur monoxide, or SO, would simply be SO, as is the empirical formula of disulfur dioxide, S2O2.

Answer : The correct option is, CH_2

Explanation :

Empirical formula : It is the simplest form of the chemical formula that depicts the whole number of atoms of each element present in the compound. It is written in the lowest possible fraction.

Molecular formula : it is the chemical formula that depicts the actual number of atoms of each element present in the compound.  

The given molecule is propene having molecular formula, C_3H_6

Now as the lowest possible fraction will be obtained when the subscripts are divide by 3.

So, the obtained empirical formula for popene is, C_{3/3}H_{6/3}=CH_2

Hence, the correct option is, CH_2

0,1 mol of carbon and 0.2 moles of hydrogen were in the original sample.

Explanation:

The combustion reaction of the compound is

C_{x} H_{y} O_{z} +O_{2} - CO_{2} + H_{2}O

And the molar mass of CO2 and H2O are 44g/mol and 18g/mol respectively

All the mass of carbon producing the CO2 must come from the carbon of the unknown compound, thus it is necessary to calculate the moles of carbon in 4.4g of CO2

\frac{4.4gx12g}{44gx12g/mol} = 0.1 mol of Carbon

Also, all the mass of hydrogen producing the H2O must come from the hydrogen of the unknown compound, hence it is necessary to calculate the moles of hydrogen in 1.8g of water

\frac{1.8gx2g}{18gx1g/mol} = 0.2 mol of Hydrogen

The empirical formula for propene (C_3H_6)[tex] is [tex]CH_2

Explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

Given : Molecular formula for propene (C_3H_6)[tex] Thus the simplest ratio of carbon and hydrogen will be 1: 2 and thus empirical formula for for propene [tex](C_3H_6)[tex] is [tex]CH_2

CH2

Explanation:

What is the empirical formula for propene (C3H6)? C2H4 C4H8 C3H6 CH2

Propene belongs  to homologous series Alkene. They have double bond connected between carbon to carbon. They are unsaturated and hence undergo addition reaction. a simple alkene compound is ethene, which can be gotten from the dehydration of ethanol in the presentnce of hydrogen tetraoxosulphate (vi) acid.

Empirical Formula is the simplest ratio in a compound

going by the formula, the propene is called a molecular formula, the empirical formula will be CH2

x(CH2)=C3H6

x=3

Therefore CH2 is the answer

The empirical formula is the simplest formula attainable while maintaining the ratio so it will be CH2



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