5difference between conductor and electrolyte ​

Answers

The most common difference between the two is that while conductors allow free flow of electrons from one atom to another, insulators restrict free flow of electrons. Conductors allow electrical energy to pass through them, whereas insulators do not allow electrical energy to pass through them.
Conductors conduct a lot semi conductors conduct a little and insulators keep it from conducting

There are three types of material as per the condition of charge flow

1) Conductor

2) Insulator

3) Semiconductor

1) Conductors

As we know that conductors are those which offer very small resistance to the flow of charge

Resistivity of the conductors are very small

2) Insulators

These type of materials offer large resistance to the flow of charges and it will not pass the current through it

So resistivity of the insulators are large as compared to conductors

Explanation:

Conductors allow free flow of electrons from one atom to another. Allow electrical energy to pass through them.

Insulators restrict free flow of electrons. Do not allow electrical energy to pass through them.

(1) A) the number of electrons surrounding the nucleus.

(2) A) valence or conduction electrons.

(3) B) reduced by a factor of 4.

(4) E) quadrupled

(5) B) It remains the same.

Explanation:

(1) The number of protons in the nucleus of an electrically neutral atom is equal to _________

protons are found in the nucleus while electrons surround the nucleus

A) the number of electrons surrounding the nucleus.

2) The main difference between conductors and insulators is in terms of _________.

conductors have mobile or free electrons while insulators have none.

A) valence or conduction electrons.

3) When the distance between the two charges is doubled, the force between them is ___________.

According to Coulomb's law;

F = \frac{Kq_1q_2}{r^2}

where;

F is the force between the charges

q₁ and q₂ are the two charges

r is the distance between the two charges

k is coulomb's constant

F = \frac{C}{r^2} , \ C = kq_1q_2\\\\F_1r_1^2 = F_2r_2^2, \ But \ r_2 = 2r_1\\\\F_2=\frac{F_1r_1^2}{r_2^2} = \frac{F_1r_1^2}{(2r_1)^2}= \frac{F_1r_1^2}{4r_1^2}\\\\F_2 = \frac{F_1}{4}

B) reduced by a factor of 4.

4) When the magnitude of both interacting charges is increased by a factor of 2, the electrical forces between these charges is _________

Apply Coulomb's law again;

F =\frac{kq_1q_2}{r^2} \\\\F = Cq_1q_2, \ C = \frac{k}{r^2} \\\\\frac{F_1}{(q_1q_2)_1} = \frac{F_2}{(q_1q_2)_2} \\\\But \ (q_1q_2)_2 = (2q_12q_2)_1 = 4(q_1q_2)_1\\\\\frac{F_1}{(q_1q_2)_1} = \frac{F_2}{4(q_1q_2)_1} \\\\F_2 = 4 F_1

E) quadrupled

5) Two charges, Q1 and Q2, are separated by a certain distance R. If the magnitudes of the charges are halved, and their separation is also halved, then what happens to the electrical force between these charges?

Apply Coulomb's law;

F = \frac{kQ_1Q_2}{R^2} \\\\k = \frac{FR^2}{Q_1Q_2} \\\\\frac{F_1R^2}{Q_1Q_2} = \frac{F_2(R/2)^2}{(Q_1/2)(Q_2/2)} \\\\\frac{F_1R^2}{Q_1Q_2} =\frac{F_2(\frac{1}{4}R^2 )}{\frac{1}{4} (Q_1Q_2)}\\\\F_2 = F_1

B) It remains the same.

There different bc there not the same

Explanation:

Common sence



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