, 24.01.2020taylorbohr6823

# Falling raindrops frequently develop electric charges. does this create noticeable forces between the droplets cabrerafreddy780

The value of developed electric force is Solution:

As per the question:

Mass of the droplet = 1.8 mg = Charge on droplet, Q = Distance between the 2 droplets, D = 0.40 cm = 0.004 m

Now, the Electrostatic force given by Coulomb:    The magnitude of force is too low to be noticed. fejwfwk1289

The electric force is Solution:

As we know that the Charge on droplet is, Distance between the 2 droplets,

r = 0.40 cm = 0.004 m

Now, the Electrostatic force given by Coulomb: here we will plug in data into above equation   erstaabi000

F = 5.83 10⁻¹⁷ N

Explanation:

The electric force is given by

F = k q₁  q₂ / r²

With Gauss's law electric field flow is equal to the charge inside the Gaussian surface, if we make a spherical surface around each drop, the force independent of small deformations due to air resistance

q₁ = q₂

F = 8.99 10⁹ (29 10⁻¹²)² / (0.36 10⁻²)²

F = 5.83 10⁻¹⁷ N

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