Molar Concentration =
Assuming 20g of the unadulterated aluminium chloride was weighed into the volumetric flask, and given molar mass of AlCl3 = 133.34g/mol
∴ Molarity =
= 0.14999 ≈ 0.15M (to 2 significant figures)
I hope this solution is clear. The same can be calculated from concentration by volume.
The question is incomplete, here is the complete question:
A chemist prepares a solution of aluminum chloride by measuring out of 11. g aluminum chloride into a 50. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's aluminum chloride solution.
The concentration of aluminium chloride solution is 1.65 mol/L
To calculate the molarity of solution, we use the equation:
We are given:
Given mass of aluminium chloride = 11. g
Molar mass of aluminium chloride = 133.34 g/mol
Volume of solution = 50. mL
Putting values in above equation, we get:
Hence, the concentration of aluminium chloride solution is 1.65 mol/L