Achemist prepares a solution of aluminum chloride by measuring out of aluminum chloride into a volumetric flask and filling the flask to the mark with water. calculate the concentration in of the chemist's aluminum chloride solution.

Answers

0.15M

Explanation:

Molar Concentration = \frac{mass}{molar mass}

Assuming 20g of the unadulterated aluminium chloride was weighed into the volumetric flask, and given molar mass of AlCl3 = 133.34g/mol

∴ Molarity = \frac{20}{133.34}

= 0.14999 ≈ 0.15M (to 2 significant figures)

I hope this solution is clear. The same can be calculated from concentration by volume.

The question is incomplete, here is the complete question:

A chemist prepares a solution of aluminum chloride by measuring out of 11. g aluminum chloride into a 50. mL volumetric flask and filling the flask to the mark with water. Calculate the concentration in mol/L of the chemist's aluminum chloride solution.

The concentration of aluminium chloride solution is 1.65 mol/L

Explanation:

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

Given mass of aluminium chloride = 11. g

Molar mass of aluminium chloride = 133.34 g/mol

Volume of solution = 50. mL

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{11\times 1000}{133.34\times 50}\\\\\text{Molarity of solution}=1.65mol/L

Hence, the concentration of aluminium chloride solution is 1.65 mol/L



Do you know the answer?

Other questions on the subject: Chemistry