3Mg + N₂ → Mg₃N₂

n(Mg) = 12,2g÷24,4g/mol = 0,5mol - limiting reagente.

n(N₂) = 5,16g÷28g/mol = 0,18mol

n(Mg₃N₂):n(Mg) = 1:3, n(Mg₃N₂) = 0,166mol

m(Mg₃N₂) = 0,166mol·101,2g/mol = 16,8g.

%(N)= 2·Ar(N)÷Mr(Mg₃N₂) = 2·14÷101,2 = 27,66% = 0,2766

%(Mg) = 3·Ar(Mg)÷Mr(Mg₃N₂) = 3·24,4÷101,2 = 72,34%

or 100% - 27,66% = 72,34%.

n(Mg) = 12,2g÷24,4g/mol = 0,5mol - limiting reagente.

n(N₂) = 5,16g÷28g/mol = 0,18mol

n(Mg₃N₂):n(Mg) = 1:3, n(Mg₃N₂) = 0,166mol

m(Mg₃N₂) = 0,166mol·101,2g/mol = 16,8g.

%(N)= 2·Ar(N)÷Mr(Mg₃N₂) = 2·14÷101,2 = 27,66% = 0,2766

%(Mg) = 3·Ar(Mg)÷Mr(Mg₃N₂) = 3·24,4÷101,2 = 72,34%

or 100% - 27,66% = 72,34%.

Explanation:

% by mass of C = (mass of C/mass of CO2) X 100%

mass of C = 12

mass of CO2 = 12 + (16X2)

= 12 + 32

= 44

% by mass of C = (12/44) X 100% =27.2%

The answer to your question is 27.3 %

Explanation:

Percent by mass = ?

Process

1.- Calculate the atomic mass of carbon using the periodic table

Atomic mass = 12g

2.- Calculate the molecular mass of CO₂.

Carbon = 12

Oxygen = 16 x 2 = 32

Total = 12 + 32 = 44g

3.- Calculate the percent by mass of carbon using proportions

44g 100%

12 g x

x = (12 x 100) / 44

x = 1200 / 44

x = 27.3 %

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