, 24.01.2020Brendah4962

# An insurance institute conducted tests with crashes of new cars traveling at 6​ mi/h. the total cost of the damages was found for a simple random sample of the tested cars and listed below. find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the given sample data. do the different measures of center differ very​ much? ​\$7 comma 454 ​\$4 comma 840 ​\$8 comma 977 ​\$6 comma 293 ​\$4 comma 253 a. the mean is ​\$ nothing. ​(type an integer or a​ decimal.) b. the median is ​\$ nothing. ​(type an integer or a​ decimal.) c. select the correct choice below and fill in any answer boxes in your choice. a. the mode is ​\$ nothing. ​(use a comma to separate answers as​ needed.) b. there is no mode. d. the midrange is ​\$ nothing. ​(type an integer or a​ decimal.) do the different measures of center differ very​ much? a. there is a very large difference between the three measures. b. only the mean is different by a large amount. c. the median and mean differ by a very large amount. d. the different measures of center do not differ by very large amounts. reyrey216

a. Mean = \$6,358.2

b. median = \$6,275

c. Mode = none

d. Midrange = \$6,647.5

There is no much difference in the measures of center.

Step-by-step explanation:

==>Given:

​\$7,402, ​\$4,819, \$8,969, ​\$6,275, ​\$4,326

==>Required:

a. Mean: sum of all values in the given sample data ÷ number of values in the sample

Mean = ​(\$7,402 + ​\$4,819 + \$8,969 + \$6,275 + \$4,326) ÷ 5

= \$31,791 ÷ 5

Mean = \$6,358.2

b. Median: this is the meddle value if the data set when ordered. Ordering the data set, we have:

\$4,326, \$4819, [\$6,275], \$7402, ​\$8,969

Our median is \$6,275.

c. Mode is the most common value in the data set. Therefore, we have no mode since there is no value in our data set that appears the most.

d. Mid-range = (highest value + lowest value) ÷ 2

= (\$8,969 + \$4,326) ÷ 2

= 13,295 ÷ 2 = \$6,647.5 legitmega

a) Mean = \$ 6378.6

b) Median = \$ 6,294

c) No mode

d) Midrange = \$ 6602

Step-by-step explanation:

Given data;

observations :

​\$7,542

​\$4,853

​\$8,989

​\$6,294

​\$4,215

total number of observations = 5

Now

a) Mean = (Sum of all the observations) / (Total number of observations )

or

Mean = (\$7,542 + ​\$4,853 + ​\$8,989 + \$6,294 + ​\$4,215) / 5

or

Mean = \$ 31893 / 5

or

Mean = \$ 6378.6

b) Median

for median, arrange the data in the ascending order, we have

\$4,215 , ​\$4,853 , ​\$6,294 , ​\$7,542 , ​\$8,989

the median of the 5 observations is the 3rd observation

hence, median = \$ 6,294

c) Mode

mode is the highest occurring observation

here every observation is unique thus no mode

d) Midrange of the given observation

Midrange = (Highest value + lowest value) / 2

or

Midrange = ( \$4,215 + ​\$8,989 ) / 2

or

Midrange = 13204 / 2

or

Midrange = \$ 6602

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