a. Mean = $6,358.2
b. median = $6,275
c. Mode = none
d. Midrange = $6,647.5
There is no much difference in the measures of center.
Step-by-step explanation:
==>Given:
$7,402, $4,819, $8,969, $6,275, $4,326
==>Required:
a. Mean: sum of all values in the given sample data ÷ number of values in the sample
Mean = ($7,402 + $4,819 + $8,969 + $6,275 + $4,326) ÷ 5
= $31,791 ÷ 5
Mean = $6,358.2
b. Median: this is the meddle value if the data set when ordered. Ordering the data set, we have:
$4,326, $4819, [$6,275], $7402, $8,969
Our median is $6,275.
c. Mode is the most common value in the data set. Therefore, we have no mode since there is no value in our data set that appears the most.
d. Mid-range = (highest value + lowest value) ÷ 2
= ($8,969 + $4,326) ÷ 2
= 13,295 ÷ 2 = $6,647.5
a) Mean = $ 6378.6
b) Median = $ 6,294
c) No mode
d) Midrange = $ 6602
Step-by-step explanation:
Given data;
observations :
$7,542
$4,853
$8,989
$6,294
$4,215
total number of observations = 5
Now
a) Mean = (Sum of all the observations) / (Total number of observations )
or
Mean = ($7,542 + $4,853 + $8,989 + $6,294 + $4,215) / 5
or
Mean = $ 31893 / 5
or
Mean = $ 6378.6
b) Median
for median, arrange the data in the ascending order, we have
$4,215 , $4,853 , $6,294 , $7,542 , $8,989
the median of the 5 observations is the 3rd observation
hence, median = $ 6,294
c) Mode
mode is the highest occurring observation
here every observation is unique thus no mode
d) Midrange of the given observation
Midrange = (Highest value + lowest value) / 2
or
Midrange = ( $4,215 + $8,989 ) / 2
or
Midrange = 13204 / 2
or
Midrange = $ 6602
Yes, the different measure of the center differs much